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Find the derivative of the following via implicit differentiation d/dx(f(x)) = d/dx(1/(1x^2)) The derivative of f(x) is f'(x) f'(x) = d/dx(1/(1x^2))Assuming that f is nonzero, we can rewrite this equation as 1 f(x) 1 f(1 / x) = 1 Making the substitution g(y) = − 1 2 1 f ( ey), we get the functional equation g(y) g( − y) = 0, which simply says that g is odd This equation can be solved, with the initial condition, by setting g(y) = cy for a suitable constant cUse the distributive property to multiply 3 x 4 − 1 8 x 3 2 4 x 2 by x 1 and combine like terms 3x^{5}15x^{4}6x^{3}24x^{2} 3 x 5 − 1 5 x 4 6 x 3 2 4 x 2
Integrate 1/(cos(x)2) from 0 to 2pi;Soll man umgekehrt die Potenz bestimmen, wenn der Logarithmus gegeben ist, so stehen die Tastenkombinationen 2nd LOG und 2nd LN bereit So berechnet man zB x=10 0,3010 durch die Tastenfolge 2nd LOG und erhält x= So berechnet man zB x=e 0,6931 durch die Tastenfolge 2nd LN und erhält x= Gerundet ist das in beiden Fällen 1,9999 oder sinnvoll gerundet 21 = (a 1 4) 2 = 2 a 2 = 8 und f 2(x) = 8x 3 und die ösung der Gleichung ist x 2 = (a 2 4) 2 = 2 (3) Wir etrbachten die unktionenF fR !R;x7!f(x) = x 3;
Simple and best practice solution for F(x)=1/x4 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,That tells us that F of X is going to be equal to negative the anti derivative of one over X is actually going to be the natural log of the absolute value of X So then based on that, what we end up having is um plus C X Class D Um And the reason why we have plus six is because this is some constant So it's anti derivative of B plus C X Ex 55, 16 Find the derivative of the function given by f (𝑥) = (1 𝑥) (1 𝑥^2) (1 𝑥^4) (1 𝑥8) and hence find f ′(1) Given 𝑓(𝑥)=(1𝑥)(1𝑥^2 )(1𝑥^4 )(1𝑥^8 )" " Let 𝑦=(1𝑥)(1𝑥^2 )(1𝑥^4 )(1𝑥^8 ) Taking log both sides log 𝑦 = log (1𝑥)(1𝑥^2 )(1𝑥^4 )(1𝑥^8 ) log 𝑦



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Consider the generating function of how many ways we can express each nonnegative integer using binary digits Firstly note that this representation is unique and hence the generating function is just 1 x x 2 x 3 ⋯ = 1 1 − x Alternatively the generating function is the product ( 1 x) ( 1 x 2) ( 1 x 4) ⋯ ( 1 x 2 n) ⋯Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledge Explanation Two straightforward ways Method One Rewrite as (1 x2)−1 and use the power and chain rules h'(x) = −(1 x2)−2 ⋅ 2x = − 2x (1 x2)2 Method Two Use the quotient rule d dx ( f (x) g(x)) = f '(x)g(x) − f (x)g'(x) (g(x))2 h'(x) = 0 −2x (1 x2)2 = − 2x (1 x2)2



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Extended Keyboard Examples Upload Random Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history, geography, engineering, mathematics, linguistics, sports, finance, music WolframAlpha brings expertlevel knowledgeGR !R;x7!g(x) = x2 1 Skizze 4 DR ROGER ROBYR Für die Schnittpunkte lösen wir die Gleichung f(x) = g(x) , x 3 = x2 1 , x2 x 4 = 0 Die zwei ösungen sind x 1;2 = 1 p 12 4 1 ( 4) 2 = ¨ 1 p 17 2 1 p 17 2 und somit die zwei The domain is x in RR The range is y in (0,1 The denominator is =1x^2 AA x in RR, 1x^2>0 Therefore, The domain of f(x) is x in RR To determine the range, proceed



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Integrate x/(x1) integrate x sin(x^2) integrate x sqrt(1sqrt(x)) integrate x/(x1)^3 from 0 to infinity;Find f f ''(x) = 24x2 2x 8, f(1) = 4, f '(1) = −3Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33



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